# Line slope calculator 4x+9y=45

**Straight line given by points A[0; 5] and B[9; 1]**

## Calculation:

**Slope-intercept form of line:**y = -0.4444x+5

**Canonical form of the line equation:**4x+9y-45 = 0

**Parametric form of the line equation:**

x = 9t

y = -4t+5 ; t ∈ R

**Slope:**m = -0.4444

**Slope angle of line: φ =**-23°57'45″ = -0.4182 rad

**X intercept:**x

_{0}= 11.25

**Y intercept:**y

_{0}= q = 5

**Distance line from the origin:**d

_{0}= 4.5691

**The length of the segment AB: |AB| =**9.8489

**Vector: AB =**(9; -4)

**Normal vector: n =**(4; 9)

**Midpoint of the segment AB: M =**[4.5; 3]

**Perpendicular Bisector equation:**9x-4y-28.5 = 0

**Vector OA = (0; 5) ; |OA| = 5**

**Vector OB = (9; 1) ; |OB| = 9.0554**

**Scalar product OA .OB = 5**

**Angle ∠ AOB = 83°39'35″ = 1.4601 rad**